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e_exp.cpp (5193B)


      1 /* @(#)e_exp.c 1.6 04/04/22 */
      2 /*
      3 * ====================================================
      4 * Copyright (C) 2004 by Sun Microsystems, Inc. All rights reserved.
      5 *
      6 * Permission to use, copy, modify, and distribute this
      7 * software is freely granted, provided that this notice 
      8 * is preserved.
      9 * ====================================================
     10 */
     11 
     12 //#include <sys/cdefs.h>
     13 //__FBSDID("$FreeBSD$");
     14 
     15 /* __ieee754_exp(x)
     16 * Returns the exponential of x.
     17 *
     18 * Method
     19 *   1. Argument reduction:
     20 *      Reduce x to an r so that |r| <= 0.5*ln2 ~ 0.34658.
     21 *	Given x, find r and integer k such that
     22 *
     23 *               x = k*ln2 + r,  |r| <= 0.5*ln2.  
     24 *
     25 *      Here r will be represented as r = hi-lo for better 
     26 *	accuracy.
     27 *
     28 *   2. Approximation of exp(r) by a special rational function on
     29 *	the interval [0,0.34658]:
     30 *	Write
     31 *	    R(r**2) = r*(exp(r)+1)/(exp(r)-1) = 2 + r*r/6 - r**4/360 + ...
     32 *      We use a special Remes algorithm on [0,0.34658] to generate 
     33 * 	a polynomial of degree 5 to approximate R. The maximum error 
     34 *	of this polynomial approximation is bounded by 2**-59. In
     35 *	other words,
     36 *	    R(z) ~ 2.0 + P1*z + P2*z**2 + P3*z**3 + P4*z**4 + P5*z**5
     37 *  	(where z=r*r, and the values of P1 to P5 are listed below)
     38 *	and
     39 *	    |                  5          |     -59
     40 *	    | 2.0+P1*z+...+P5*z   -  R(z) | <= 2 
     41 *	    |                             |
     42 *	The computation of exp(r) thus becomes
     43 *                             2*r
     44 *		exp(r) = 1 + -------
     45 *		              R - r
     46 *                                 r*R1(r)	
     47 *		       = 1 + r + ----------- (for better accuracy)
     48 *		                  2 - R1(r)
     49 *	where
     50 *			         2       4             10
     51 *		R1(r) = r - (P1*r  + P2*r  + ... + P5*r   ).
     52 *	
     53 *   3. Scale back to obtain exp(x):
     54 *	From step 1, we have
     55 *	   exp(x) = 2^k * exp(r)
     56 *
     57 * Special cases:
     58 *	exp(INF) is INF, exp(NaN) is NaN;
     59 *	exp(-INF) is 0, and
     60 *	for finite argument, only exp(0)=1 is exact.
     61 *
     62 * Accuracy:
     63 *	according to an error analysis, the error is always less than
     64 *	1 ulp (unit in the last place).
     65 *
     66 * Misc. info.
     67 *	For IEEE double 
     68 *	    if x >  7.09782712893383973096e+02 then exp(x) overflow
     69 *	    if x < -7.45133219101941108420e+02 then exp(x) underflow
     70 *
     71 * Constants:
     72 * The hexadecimal values are the intended ones for the following 
     73 * constants. The decimal values may be used, provided that the 
     74 * compiler will convert from decimal to binary accurately enough
     75 * to produce the hexadecimal values shown.
     76 */
     77 
     78 #include <float.h>
     79 
     80 #include "math_private.h"
     81 
     82 static const double
     83 one	= 1.0,
     84 halF[2]	= {0.5,-0.5,},
     85 o_threshold=  7.09782712893383973096e+02,  /* 0x40862E42, 0xFEFA39EF */
     86 u_threshold= -7.45133219101941108420e+02,  /* 0xc0874910, 0xD52D3051 */
     87 ln2HI[2]   ={ 6.93147180369123816490e-01,  /* 0x3fe62e42, 0xfee00000 */
     88      -6.93147180369123816490e-01,},/* 0xbfe62e42, 0xfee00000 */
     89 ln2LO[2]   ={ 1.90821492927058770002e-10,  /* 0x3dea39ef, 0x35793c76 */
     90      -1.90821492927058770002e-10,},/* 0xbdea39ef, 0x35793c76 */
     91 invln2 =  1.44269504088896338700e+00, /* 0x3ff71547, 0x652b82fe */
     92 P1   =  1.66666666666666019037e-01, /* 0x3FC55555, 0x5555553E */
     93 P2   = -2.77777777770155933842e-03, /* 0xBF66C16C, 0x16BEBD93 */
     94 P3   =  6.61375632143793436117e-05, /* 0x3F11566A, 0xAF25DE2C */
     95 P4   = -1.65339022054652515390e-06, /* 0xBEBBBD41, 0xC5D26BF1 */
     96 P5   =  4.13813679705723846039e-08; /* 0x3E663769, 0x72BEA4D0 */
     97 
     98 static const double E = 2.7182818284590452354;	/* e */
     99 
    100 static volatile double
    101 huge	= 1.0e+300,
    102 twom1000= 9.33263618503218878990e-302;     /* 2**-1000=0x01700000,0*/
    103 
    104 double
    105 __ieee754_exp(double x)	/* default IEEE double exp */
    106 {
    107 double y,hi=0.0,lo=0.0,c,t,twopk;
    108 int32_t k=0,xsb;
    109 u_int32_t hx;
    110 
    111 GET_HIGH_WORD(hx,x);
    112 xsb = (hx>>31)&1;		/* sign bit of x */
    113 hx &= 0x7fffffff;		/* high word of |x| */
    114 
    115    /* filter out non-finite argument */
    116 if(hx >= 0x40862E42) {			/* if |x|>=709.78... */
    117            if(hx>=0x7ff00000) {
    118         u_int32_t lx;
    119 	GET_LOW_WORD(lx,x);
    120 	if(((hx&0xfffff)|lx)!=0)
    121 	     return x+x; 		/* NaN */
    122 	else return (xsb==0)? x:0.0;	/* exp(+-inf)={inf,0} */
    123     }
    124     if(x > o_threshold) return huge*huge; /* overflow */
    125     if(x < u_threshold) return twom1000*twom1000; /* underflow */
    126 }
    127 
    128    /* argument reduction */
    129 if(hx > 0x3fd62e42) {		/* if  |x| > 0.5 ln2 */ 
    130     if(hx < 0x3FF0A2B2) {	/* and |x| < 1.5 ln2 */
    131 	if (x == 1.0) return E;
    132 	hi = x-ln2HI[xsb]; lo=ln2LO[xsb]; k = 1-xsb-xsb;
    133     } else {
    134 	k  = (int)(invln2*x+halF[xsb]);
    135 	t  = k;
    136 	hi = x - t*ln2HI[0];	/* t*ln2HI is exact here */
    137 	lo = t*ln2LO[0];
    138     }
    139     STRICT_ASSIGN(double, x, hi - lo);
    140 } 
    141 else if(hx < 0x3e300000)  {	/* when |x|<2**-28 */
    142     if(huge+x>one) return one+x;/* trigger inexact */
    143 }
    144 else k = 0;
    145 
    146    /* x is now in primary range */
    147 t  = x*x;
    148 if(k >= -1021)
    149     INSERT_WORDS(twopk,((u_int32_t)(0x3ff+k))<<20, 0);
    150 else
    151     INSERT_WORDS(twopk,((u_int32_t)(0x3ff+(k+1000)))<<20, 0);
    152 c  = x - t*(P1+t*(P2+t*(P3+t*(P4+t*P5))));
    153 if(k==0) 	return one-((x*c)/(c-2.0)-x); 
    154 else 		y = one-((lo-(x*c)/(2.0-c))-hi);
    155 if(k >= -1021) {
    156     if (k==1024) return y*2.0*0x1p1023;
    157     return y*twopk;
    158 } else {
    159     return y*twopk*twom1000;
    160 }
    161 }